Integrand size = 25, antiderivative size = 557 \[ \int \frac {(e \cos (c+d x))^{13/2}}{(a+b \sin (c+d x))^4} \, dx=\frac {77 a \left (3 a^2-2 b^2\right ) e^{13/2} \arctan \left (\frac {\sqrt {b} \sqrt {e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt {e}}\right )}{16 b^{13/2} \sqrt [4]{-a^2+b^2} d}-\frac {77 a \left (3 a^2-2 b^2\right ) e^{13/2} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt {e}}\right )}{16 b^{13/2} \sqrt [4]{-a^2+b^2} d}-\frac {77 \left (15 a^2-4 b^2\right ) e^6 \sqrt {e \cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{40 b^6 d \sqrt {\cos (c+d x)}}+\frac {77 a^2 \left (3 a^2-2 b^2\right ) e^7 \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 b}{b-\sqrt {-a^2+b^2}},\frac {1}{2} (c+d x),2\right )}{16 b^7 \left (b-\sqrt {-a^2+b^2}\right ) d \sqrt {e \cos (c+d x)}}+\frac {77 a^2 \left (3 a^2-2 b^2\right ) e^7 \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 b}{b+\sqrt {-a^2+b^2}},\frac {1}{2} (c+d x),2\right )}{16 b^7 \left (b+\sqrt {-a^2+b^2}\right ) d \sqrt {e \cos (c+d x)}}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}-\frac {11 e^3 (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{60 b^3 d (a+b \sin (c+d x))^2}-\frac {77 e^5 (e \cos (c+d x))^{3/2} \left (15 a^2-4 b^2+6 a b \sin (c+d x)\right )}{120 b^5 d (a+b \sin (c+d x))} \]
77/16*a*(3*a^2-2*b^2)*e^(13/2)*arctan(b^(1/2)*(e*cos(d*x+c))^(1/2)/(-a^2+b ^2)^(1/4)/e^(1/2))/b^(13/2)/(-a^2+b^2)^(1/4)/d-77/16*a*(3*a^2-2*b^2)*e^(13 /2)*arctanh(b^(1/2)*(e*cos(d*x+c))^(1/2)/(-a^2+b^2)^(1/4)/e^(1/2))/b^(13/2 )/(-a^2+b^2)^(1/4)/d-1/3*e*(e*cos(d*x+c))^(11/2)/b/d/(a+b*sin(d*x+c))^3-11 /60*e^3*(e*cos(d*x+c))^(7/2)*(9*a+4*b*sin(d*x+c))/b^3/d/(a+b*sin(d*x+c))^2 -77/120*e^5*(e*cos(d*x+c))^(3/2)*(15*a^2-4*b^2+6*a*b*sin(d*x+c))/b^5/d/(a+ b*sin(d*x+c))+77/16*a^2*(3*a^2-2*b^2)*e^7*(cos(1/2*d*x+1/2*c)^2)^(1/2)/cos (1/2*d*x+1/2*c)*EllipticPi(sin(1/2*d*x+1/2*c),2*b/(b-(-a^2+b^2)^(1/2)),2^( 1/2))*cos(d*x+c)^(1/2)/b^7/d/(b-(-a^2+b^2)^(1/2))/(e*cos(d*x+c))^(1/2)+77/ 16*a^2*(3*a^2-2*b^2)*e^7*(cos(1/2*d*x+1/2*c)^2)^(1/2)/cos(1/2*d*x+1/2*c)*E llipticPi(sin(1/2*d*x+1/2*c),2*b/(b+(-a^2+b^2)^(1/2)),2^(1/2))*cos(d*x+c)^ (1/2)/b^7/d/(b+(-a^2+b^2)^(1/2))/(e*cos(d*x+c))^(1/2)-77/40*(15*a^2-4*b^2) *e^6*(cos(1/2*d*x+1/2*c)^2)^(1/2)/cos(1/2*d*x+1/2*c)*EllipticE(sin(1/2*d*x +1/2*c),2^(1/2))*(e*cos(d*x+c))^(1/2)/b^6/d/cos(d*x+c)^(1/2)
Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
Time = 22.94 (sec) , antiderivative size = 937, normalized size of antiderivative = 1.68 \[ \int \frac {(e \cos (c+d x))^{13/2}}{(a+b \sin (c+d x))^4} \, dx=-\frac {77 (e \cos (c+d x))^{13/2} \left (-\frac {12 a b \left (a+b \sqrt {1-\cos ^2(c+d x)}\right ) \left (\frac {a \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{2},1,\frac {7}{4},\cos ^2(c+d x),\frac {b^2 \cos ^2(c+d x)}{-a^2+b^2}\right ) \cos ^{\frac {3}{2}}(c+d x)}{3 \left (a^2-b^2\right )}+\frac {\left (\frac {1}{8}+\frac {i}{8}\right ) \left (2 \arctan \left (1-\frac {(1+i) \sqrt {b} \sqrt {\cos (c+d x)}}{\sqrt [4]{-a^2+b^2}}\right )-2 \arctan \left (1+\frac {(1+i) \sqrt {b} \sqrt {\cos (c+d x)}}{\sqrt [4]{-a^2+b^2}}\right )-\log \left (\sqrt {-a^2+b^2}-(1+i) \sqrt {b} \sqrt [4]{-a^2+b^2} \sqrt {\cos (c+d x)}+i b \cos (c+d x)\right )+\log \left (\sqrt {-a^2+b^2}+(1+i) \sqrt {b} \sqrt [4]{-a^2+b^2} \sqrt {\cos (c+d x)}+i b \cos (c+d x)\right )\right )}{\sqrt {b} \sqrt [4]{-a^2+b^2}}\right ) \sin (c+d x)}{\sqrt {1-\cos ^2(c+d x)} (a+b \sin (c+d x))}-\frac {\left (15 a^2-4 b^2\right ) \left (a+b \sqrt {1-\cos ^2(c+d x)}\right ) \left (8 b^{5/2} \operatorname {AppellF1}\left (\frac {3}{4},-\frac {1}{2},1,\frac {7}{4},\cos ^2(c+d x),\frac {b^2 \cos ^2(c+d x)}{-a^2+b^2}\right ) \cos ^{\frac {3}{2}}(c+d x)+3 \sqrt {2} a \left (a^2-b^2\right )^{3/4} \left (2 \arctan \left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {\cos (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )-2 \arctan \left (1+\frac {\sqrt {2} \sqrt {b} \sqrt {\cos (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )-\log \left (\sqrt {a^2-b^2}-\sqrt {2} \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\cos (c+d x)}+b \cos (c+d x)\right )+\log \left (\sqrt {a^2-b^2}+\sqrt {2} \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\cos (c+d x)}+b \cos (c+d x)\right )\right )\right ) \sin ^2(c+d x)}{12 b^{3/2} \left (-a^2+b^2\right ) \left (1-\cos ^2(c+d x)\right ) (a+b \sin (c+d x))}\right )}{80 b^5 d \cos ^{\frac {13}{2}}(c+d x)}+\frac {(e \cos (c+d x))^{13/2} \sec ^6(c+d x) \left (-\frac {8 a \cos (c+d x)}{3 b^5}+\frac {-a^4 \cos (c+d x)+2 a^2 b^2 \cos (c+d x)-b^4 \cos (c+d x)}{3 b^5 (a+b \sin (c+d x))^3}+\frac {9 \left (a^3 \cos (c+d x)-a b^2 \cos (c+d x)\right )}{4 b^5 (a+b \sin (c+d x))^2}+\frac {-71 a^2 \cos (c+d x)+20 b^2 \cos (c+d x)}{8 b^5 (a+b \sin (c+d x))}+\frac {\sin (2 (c+d x))}{5 b^4}\right )}{d} \]
(-77*(e*Cos[c + d*x])^(13/2)*((-12*a*b*(a + b*Sqrt[1 - Cos[c + d*x]^2])*(( a*AppellF1[3/4, 1/2, 1, 7/4, Cos[c + d*x]^2, (b^2*Cos[c + d*x]^2)/(-a^2 + b^2)]*Cos[c + d*x]^(3/2))/(3*(a^2 - b^2)) + ((1/8 + I/8)*(2*ArcTan[1 - ((1 + I)*Sqrt[b]*Sqrt[Cos[c + d*x]])/(-a^2 + b^2)^(1/4)] - 2*ArcTan[1 + ((1 + I)*Sqrt[b]*Sqrt[Cos[c + d*x]])/(-a^2 + b^2)^(1/4)] - Log[Sqrt[-a^2 + b^2] - (1 + I)*Sqrt[b]*(-a^2 + b^2)^(1/4)*Sqrt[Cos[c + d*x]] + I*b*Cos[c + d*x ]] + Log[Sqrt[-a^2 + b^2] + (1 + I)*Sqrt[b]*(-a^2 + b^2)^(1/4)*Sqrt[Cos[c + d*x]] + I*b*Cos[c + d*x]]))/(Sqrt[b]*(-a^2 + b^2)^(1/4)))*Sin[c + d*x])/ (Sqrt[1 - Cos[c + d*x]^2]*(a + b*Sin[c + d*x])) - ((15*a^2 - 4*b^2)*(a + b *Sqrt[1 - Cos[c + d*x]^2])*(8*b^(5/2)*AppellF1[3/4, -1/2, 1, 7/4, Cos[c + d*x]^2, (b^2*Cos[c + d*x]^2)/(-a^2 + b^2)]*Cos[c + d*x]^(3/2) + 3*Sqrt[2]* a*(a^2 - b^2)^(3/4)*(2*ArcTan[1 - (Sqrt[2]*Sqrt[b]*Sqrt[Cos[c + d*x]])/(a^ 2 - b^2)^(1/4)] - 2*ArcTan[1 + (Sqrt[2]*Sqrt[b]*Sqrt[Cos[c + d*x]])/(a^2 - b^2)^(1/4)] - Log[Sqrt[a^2 - b^2] - Sqrt[2]*Sqrt[b]*(a^2 - b^2)^(1/4)*Sqr t[Cos[c + d*x]] + b*Cos[c + d*x]] + Log[Sqrt[a^2 - b^2] + Sqrt[2]*Sqrt[b]* (a^2 - b^2)^(1/4)*Sqrt[Cos[c + d*x]] + b*Cos[c + d*x]]))*Sin[c + d*x]^2)/( 12*b^(3/2)*(-a^2 + b^2)*(1 - Cos[c + d*x]^2)*(a + b*Sin[c + d*x]))))/(80*b ^5*d*Cos[c + d*x]^(13/2)) + ((e*Cos[c + d*x])^(13/2)*Sec[c + d*x]^6*((-8*a *Cos[c + d*x])/(3*b^5) + (-(a^4*Cos[c + d*x]) + 2*a^2*b^2*Cos[c + d*x] - b ^4*Cos[c + d*x])/(3*b^5*(a + b*Sin[c + d*x])^3) + (9*(a^3*Cos[c + d*x] ...
Time = 2.56 (sec) , antiderivative size = 526, normalized size of antiderivative = 0.94, number of steps used = 24, number of rules used = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.920, Rules used = {3042, 3172, 3042, 3342, 27, 3042, 3342, 27, 3042, 3346, 3042, 3121, 3042, 3119, 3180, 266, 827, 218, 221, 3042, 3286, 3042, 3284}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {(e \cos (c+d x))^{13/2}}{(a+b \sin (c+d x))^4} \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {(e \cos (c+d x))^{13/2}}{(a+b \sin (c+d x))^4}dx\) |
| \(\Big \downarrow \) 3172 |
| \(\displaystyle -\frac {11 e^2 \int \frac {(e \cos (c+d x))^{9/2} \sin (c+d x)}{(a+b \sin (c+d x))^3}dx}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {11 e^2 \int \frac {(e \cos (c+d x))^{9/2} \sin (c+d x)}{(a+b \sin (c+d x))^3}dx}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3342 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}-\frac {7 e^2 \int -\frac {(e \cos (c+d x))^{5/2} (4 b+9 a \sin (c+d x))}{2 (a+b \sin (c+d x))^2}dx}{10 b^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \int \frac {(e \cos (c+d x))^{5/2} (4 b+9 a \sin (c+d x))}{(a+b \sin (c+d x))^2}dx}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \int \frac {(e \cos (c+d x))^{5/2} (4 b+9 a \sin (c+d x))}{(a+b \sin (c+d x))^2}dx}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3342 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}-\frac {e^2 \int -\frac {3 \sqrt {e \cos (c+d x)} \left (6 a b+\left (15 a^2-4 b^2\right ) \sin (c+d x)\right )}{2 (a+b \sin (c+d x))}dx}{b^2}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \int \frac {\sqrt {e \cos (c+d x)} \left (6 a b+\left (15 a^2-4 b^2\right ) \sin (c+d x)\right )}{a+b \sin (c+d x)}dx}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \int \frac {\sqrt {e \cos (c+d x)} \left (6 a b+\left (15 a^2-4 b^2\right ) \sin (c+d x)\right )}{a+b \sin (c+d x)}dx}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3346 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {\left (15 a^2-4 b^2\right ) \int \sqrt {e \cos (c+d x)}dx}{b}-\frac {5 a \left (3 a^2-2 b^2\right ) \int \frac {\sqrt {e \cos (c+d x)}}{a+b \sin (c+d x)}dx}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {\left (15 a^2-4 b^2\right ) \int \sqrt {e \sin \left (c+d x+\frac {\pi }{2}\right )}dx}{b}-\frac {5 a \left (3 a^2-2 b^2\right ) \int \frac {\sqrt {e \cos (c+d x)}}{a+b \sin (c+d x)}dx}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3121 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {\left (15 a^2-4 b^2\right ) \sqrt {e \cos (c+d x)} \int \sqrt {\cos (c+d x)}dx}{b \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \int \frac {\sqrt {e \cos (c+d x)}}{a+b \sin (c+d x)}dx}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {\left (15 a^2-4 b^2\right ) \sqrt {e \cos (c+d x)} \int \sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}dx}{b \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \int \frac {\sqrt {e \cos (c+d x)}}{a+b \sin (c+d x)}dx}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3119 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {2 \left (15 a^2-4 b^2\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{b d \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \int \frac {\sqrt {e \cos (c+d x)}}{a+b \sin (c+d x)}dx}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3180 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {2 \left (15 a^2-4 b^2\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{b d \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \left (\frac {b e \int \frac {\sqrt {e \cos (c+d x)}}{b^2 \cos ^2(c+d x) e^2+\left (a^2-b^2\right ) e^2}d(e \cos (c+d x))}{d}-\frac {a e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}\right )}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 266 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {2 \left (15 a^2-4 b^2\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{b d \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \left (\frac {2 b e \int \frac {e^2 \cos ^2(c+d x)}{b^2 e^4 \cos ^4(c+d x)+\left (a^2-b^2\right ) e^2}d\sqrt {e \cos (c+d x)}}{d}-\frac {a e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}\right )}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 827 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {2 \left (15 a^2-4 b^2\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{b d \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \left (\frac {2 b e \left (\frac {\int \frac {1}{b e^2 \cos ^2(c+d x)+\sqrt {b^2-a^2} e}d\sqrt {e \cos (c+d x)}}{2 b}-\frac {\int \frac {1}{\sqrt {b^2-a^2} e-b e^2 \cos ^2(c+d x)}d\sqrt {e \cos (c+d x)}}{2 b}\right )}{d}-\frac {a e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}\right )}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 218 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {2 \left (15 a^2-4 b^2\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{b d \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \left (\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\int \frac {1}{\sqrt {b^2-a^2} e-b e^2 \cos ^2(c+d x)}d\sqrt {e \cos (c+d x)}}{2 b}\right )}{d}-\frac {a e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}\right )}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 221 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {2 \left (15 a^2-4 b^2\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{b d \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \left (-\frac {a e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b}+\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{d}\right )}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {2 \left (15 a^2-4 b^2\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{b d \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \left (-\frac {a e \int \frac {1}{\sqrt {e \sin \left (c+d x+\frac {\pi }{2}\right )} \left (\sqrt {b^2-a^2}-b \sin \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{2 b}+\frac {a e \int \frac {1}{\sqrt {e \sin \left (c+d x+\frac {\pi }{2}\right )} \left (b \sin \left (c+d x+\frac {\pi }{2}\right )+\sqrt {b^2-a^2}\right )}dx}{2 b}+\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{d}\right )}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3286 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {2 \left (15 a^2-4 b^2\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{b d \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \left (-\frac {a e \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 b \sqrt {e \cos (c+d x)}}+\frac {a e \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 b \sqrt {e \cos (c+d x)}}+\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{d}\right )}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {2 \left (15 a^2-4 b^2\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{b d \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \left (-\frac {a e \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )} \left (\sqrt {b^2-a^2}-b \sin \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{2 b \sqrt {e \cos (c+d x)}}+\frac {a e \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )} \left (b \sin \left (c+d x+\frac {\pi }{2}\right )+\sqrt {b^2-a^2}\right )}dx}{2 b \sqrt {e \cos (c+d x)}}+\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{d}\right )}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3284 |
| \(\displaystyle -\frac {11 e^2 \left (\frac {7 e^2 \left (\frac {3 e^2 \left (\frac {2 \left (15 a^2-4 b^2\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {e \cos (c+d x)}}{b d \sqrt {\cos (c+d x)}}-\frac {5 a \left (3 a^2-2 b^2\right ) \left (\frac {2 b e \left (\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 b^{3/2} \sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{d}+\frac {a e \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 b}{b-\sqrt {b^2-a^2}},\frac {1}{2} (c+d x),2\right )}{b d \left (b-\sqrt {b^2-a^2}\right ) \sqrt {e \cos (c+d x)}}+\frac {a e \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 b}{b+\sqrt {b^2-a^2}},\frac {1}{2} (c+d x),2\right )}{b d \left (\sqrt {b^2-a^2}+b\right ) \sqrt {e \cos (c+d x)}}\right )}{b}\right )}{2 b^2}+\frac {e (e \cos (c+d x))^{3/2} \left (15 a^2+6 a b \sin (c+d x)-4 b^2\right )}{b^2 d (a+b \sin (c+d x))}\right )}{20 b^2}+\frac {e (e \cos (c+d x))^{7/2} (9 a+4 b \sin (c+d x))}{10 b^2 d (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e (e \cos (c+d x))^{11/2}}{3 b d (a+b \sin (c+d x))^3}\) |
-1/3*(e*(e*Cos[c + d*x])^(11/2))/(b*d*(a + b*Sin[c + d*x])^3) - (11*e^2*(( e*(e*Cos[c + d*x])^(7/2)*(9*a + 4*b*Sin[c + d*x]))/(10*b^2*d*(a + b*Sin[c + d*x])^2) + (7*e^2*((3*e^2*((2*(15*a^2 - 4*b^2)*Sqrt[e*Cos[c + d*x]]*Elli pticE[(c + d*x)/2, 2])/(b*d*Sqrt[Cos[c + d*x]]) - (5*a*(3*a^2 - 2*b^2)*((2 *b*e*(ArcTan[(Sqrt[b]*Sqrt[e]*Cos[c + d*x])/(-a^2 + b^2)^(1/4)]/(2*b^(3/2) *(-a^2 + b^2)^(1/4)*Sqrt[e]) - ArcTanh[(Sqrt[b]*Sqrt[e]*Cos[c + d*x])/(-a^ 2 + b^2)^(1/4)]/(2*b^(3/2)*(-a^2 + b^2)^(1/4)*Sqrt[e])))/d + (a*e*Sqrt[Cos [c + d*x]]*EllipticPi[(2*b)/(b - Sqrt[-a^2 + b^2]), (c + d*x)/2, 2])/(b*(b - Sqrt[-a^2 + b^2])*d*Sqrt[e*Cos[c + d*x]]) + (a*e*Sqrt[Cos[c + d*x]]*Ell ipticPi[(2*b)/(b + Sqrt[-a^2 + b^2]), (c + d*x)/2, 2])/(b*(b + Sqrt[-a^2 + b^2])*d*Sqrt[e*Cos[c + d*x]])))/b))/(2*b^2) + (e*(e*Cos[c + d*x])^(3/2)*( 15*a^2 - 4*b^2 + 6*a*b*Sin[c + d*x]))/(b^2*d*(a + b*Sin[c + d*x]))))/(20*b ^2)))/(6*b)
3.7.6.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2]], s = Denominator[Rt[-a/b, 2]]}, Simp[s/(2*b) Int[1/(r + s*x^2), x], x] - Simp[s/(2*b) Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] && !GtQ [a/b, 0]
Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)* (c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
Int[((b_)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*Sin[c + d*x]) ^n/Sin[c + d*x]^n Int[Sin[c + d*x]^n, x], x] /; FreeQ[{b, c, d}, x] && Lt Q[-1, n, 1] && IntegerQ[2*n]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[g*(g*Cos[e + f*x])^(p - 1)*((a + b*Sin[e + f*x ])^(m + 1)/(b*f*(m + 1))), x] + Simp[g^2*((p - 1)/(b*(m + 1))) Int[(g*Cos [e + f*x])^(p - 2)*(a + b*Sin[e + f*x])^(m + 1)*Sin[e + f*x], x], x] /; Fre eQ[{a, b, e, f, g}, x] && NeQ[a^2 - b^2, 0] && LtQ[m, -1] && GtQ[p, 1] && I ntegersQ[2*m, 2*p]
Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(g_.)]/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_ )]), x_Symbol] :> With[{q = Rt[-a^2 + b^2, 2]}, Simp[a*(g/(2*b)) Int[1/(S qrt[g*Cos[e + f*x]]*(q + b*Cos[e + f*x])), x], x] + (-Simp[a*(g/(2*b)) In t[1/(Sqrt[g*Cos[e + f*x]]*(q - b*Cos[e + f*x])), x], x] + Simp[b*(g/f) Su bst[Int[Sqrt[x]/(g^2*(a^2 - b^2) + b^2*x^2), x], x, g*Cos[e + f*x]], x])] / ; FreeQ[{a, b, e, f, g}, x] && NeQ[a^2 - b^2, 0]
Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]]), x_Symbol] :> Simp[(2/(f*(a + b)*Sqrt[c + d]))*EllipticPi[ 2*(b/(a + b)), (1/2)*(e - Pi/2 + f*x), 2*(d/(c + d))], x] /; FreeQ[{a, b, c , d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[c + d, 0]
Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]]), x_Symbol] :> Simp[Sqrt[(c + d*Sin[e + f*x])/(c + d)]/Sqrt [c + d*Sin[e + f*x]] Int[1/((a + b*Sin[e + f*x])*Sqrt[c/(c + d) + (d/(c + d))*Sin[e + f*x]]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a* d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && !GtQ[c + d, 0]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[g*(g*C os[e + f*x])^(p - 1)*(a + b*Sin[e + f*x])^(m + 1)*((b*c*(m + p + 1) - a*d*p + b*d*(m + 1)*Sin[e + f*x])/(b^2*f*(m + 1)*(m + p + 1))), x] + Simp[g^2*(( p - 1)/(b^2*(m + 1)*(m + p + 1))) Int[(g*Cos[e + f*x])^(p - 2)*(a + b*Sin [e + f*x])^(m + 1)*Simp[b*d*(m + 1) + (b*c*(m + p + 1) - a*d*p)*Sin[e + f*x ], x], x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[a^2 - b^2, 0] && Lt Q[m, -1] && GtQ[p, 1] && NeQ[m + p + 1, 0] && IntegerQ[2*m]
Int[((cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((c_.) + (d_.)*sin[(e_.) + (f_.)* (x_)]))/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[d/b Int [(g*Cos[e + f*x])^p, x], x] + Simp[(b*c - a*d)/b Int[(g*Cos[e + f*x])^p/( a + b*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[a^2 - b^2, 0]
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 339.69 (sec) , antiderivative size = 5058, normalized size of antiderivative = 9.08
Timed out. \[ \int \frac {(e \cos (c+d x))^{13/2}}{(a+b \sin (c+d x))^4} \, dx=\text {Timed out} \]
Timed out. \[ \int \frac {(e \cos (c+d x))^{13/2}}{(a+b \sin (c+d x))^4} \, dx=\text {Timed out} \]
Timed out. \[ \int \frac {(e \cos (c+d x))^{13/2}}{(a+b \sin (c+d x))^4} \, dx=\text {Timed out} \]
Timed out. \[ \int \frac {(e \cos (c+d x))^{13/2}}{(a+b \sin (c+d x))^4} \, dx=\text {Timed out} \]
Timed out. \[ \int \frac {(e \cos (c+d x))^{13/2}}{(a+b \sin (c+d x))^4} \, dx=\int \frac {{\left (e\,\cos \left (c+d\,x\right )\right )}^{13/2}}{{\left (a+b\,\sin \left (c+d\,x\right )\right )}^4} \,d x \]